A cura di: Alfredo Bochicchio
$[(1/2ab-(1/4a+b)^2+(b+1/4a)(-1/4a+b)]a+(b+1/2a)^3-b^2(3/2a+b)$
$[1/2ab-1/16a^2-1/2ab-b^2+b^2-1/16a^2]a+b^3+3/2ab^2+3/4a^2b+1/8a^3-3/2ab^2-b^3$
$-2/16a^3+3/4a^2b+1/8a^3$
$3/4a^2b$
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