A cura di: Alfredo Bochicchio
${[(-1/4a^2b^4)^2-(+1/2ab^2)^4-(-ab^2)^4]:(1/2a^2b)^2}^2:(2b)^3$
${(1/16a^7b^8)-(1/16a^4b^8)-a^4b^8]:(1/4a^4b^2)}^2:(8b^3)$
${-a^4b^8:(1/4a^4b^2)}^2:(8b^3)$
${-4b^6}^2:(8b^3)$
$16b^2:8b^3$
$2b^9$
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