$2ab^2-[1/3ab+3ab^2+(a^2b^2-4a^2b^2):(ab)-1/3ab]-3a(-b^2)+ab-2ab^2$

A cura di: Francesco Speciale

Svolgimento:
$2ab^2-[1/3ab+3ab^2+(a^2b^2-4a^2b^2):(ab)-1/3ab]-3a(-b^2)+ab-2ab^2=$
$=2ab^2-[+3ab^2+(-3a^2b^2):(ab)]+3ab^2+ab-2ab^2=$
$=2ab^2-[+3ab^2-3ab]+ab^2+ab=$
$=2ab^2-3ab^2+3ab+ab^2+ab=4ab$.