$2sin((\pi)/6)-3cos((\pi)/3)+tg(4/3(\pi))+3cotg(5/6(\pi))$

A cura di: Francesco Speciale

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Calcolare il valore della seguente espressione:
$2sin((pi)/6)-3cos((pi)/3)+tg(4/3(pi))+3cotg(5/6(pi))$

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$2sin((pi)/6)-3cos((pi)/3)+tg(4/3(pi))+3cotg(5/6(pi))=$

Essendo $cos((pi)/3)=1/2=sin((pi)/6) , tg(4/3(pi))=sqrt3 , cotg(5/6(pi))=-sqrt3$,
sostituendo nell’espressione si ha:
$=2(1/2)+3(1/2)+sqrt3+3(-sqrt3)=1+3/2+sqrt3-3sqrt3=5/2-2sqrt3$.