$f(x) = \sqrt{1 + x^2} = (1 + x^2)^{1/2}$

A cura di: Administrator

Derivare la funzione:

$f(x) = sqrt{1 + x^2} = (1 + x^2)^{1/2}$; $f'(x) = frac{1}{2} (1 + x^2)^{1/2 – 1} cdot 2x =$ $frac{x}{sqrt{1 + x^2}}$