A cura di: Gianluca
$int(3-7x)/(4+2x^2)dx=$
=$int3dx/(4+2x^2)-7intx/(4+2x^2)dx=$
=$3/4intdx/(1+x^2/2)-7/4(log4+2x^2)=$
=$(3/4arctan(x/sqrt(2)))/(1/sqrt(2))-7/4(log(4+2x^2))+K$
di Anoè Gianluca –www.chenesoio.com
- Integrali
- Matematica - Integrali
$\int(3-7x)/(4+2x^2)dx=$
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