$\lim_{x \rightarrow -\infty}\frac{2x-5}{x^2+1}=$

A cura di: Administrator

Limite in forma indeterminata $frac{infty}{infty}$

$lim_{x rightarrow -infty}frac{2x-5}{x^2+1}=$

$=lim_{x rightarrow -infty}frac{xcdot (2-frac{5}{x})}{x^2cdot (1+frac{1}{x^2})}=0$