$lim_{xto 2}((x^2-5x+6)/(x^3+2x^2-4x-8))$

A cura di: Administrator

Limite in forma indeterminata $frac{0}{0}$

$lim_{x rightarrow 2} frac{x^2-5x+6}{x^3+2x^2-4x-8}=$$lim_{x rightarrow 2} frac{(x-3) (x-2)}{x^2 (x+2) – 4 (x+2)}=$$= lim_{x rightarrow 2} frac{(x-3) (x-2)}{(x-2) (x+2)^2} = -frac{1}{16}$