$lim_{xto 3}((x^2-4x+3)/(2x-6))$

A cura di: Administrator

Limite in forma indeterminata $frac{0}{0}$

$lim_{x rightarrow 3} frac{x^2-4x+3}{2x-6} =$$= lim_{x rightarrow 3} frac{(x-1) (x-3)}{2cdot (x-3)}=$$= lim_{x rightarrow 3} frac{x-1}{2} = 1$