$lim_{xto-4}(1/(2x+8)+4/(x^2-16))$

A cura di: Administrator

Limite in forma indeterminata $infty – infty$

$lim_{x rightarrow -4} (frac{1}{2x+8}+frac{4}{x^2-16})=$$lim_{x rightarrow -4} (frac{1}{2 (x+4)}+frac{4}{(x+4) (x-4)})$$lim_{x rightarrow -4} frac{(x-4)+2cdot 4}{2 (x+4) (x-4)} =$$lim_{x rightarrow -4} frac{x+4}{2 (x+4) (x-4)} =$$lim_{x rightarrow -4} frac{1}{2 (x-4)} = -frac{1}{16}$