$x/(bx+b-x-1) - x/(bx+b+x+1) - 2/(b^2 -1)$

A cura di: Antonio Bernardo

$x/(bx+b-x-1) – x/(bx+b+x+1) – 2/(b^2 -1)$

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Scompongo in fattori i denominatori raccogliendo a fattore comune parziale

$x/(b(x+1)-(x+1))- x/(b(x+1)+(x+1)) – 2/((b-1)(b+1))$

$x/((x+1)(b-1)) – x/((x+1)(b+1)) – 2/((b-1)(b+1))$

procedo con il m.c.m.

$(x(b+1)-x(b-1)-2(x+1))/((x+1)(b+1)(b-1))$

moltiplo

$(xb+x-xb+x-2x-2)/((x+1)(b+1)(b-1))$

$-2/((x+1)(b+1)(b-1))$